Web5 Answers. Sorted by: 147. One easy way would be to groupby the first level of the index - iterating over the groupby object will return the group keys and a subframe containing each group. In [136]: for date, new_df in df.groupby (level=0): ...: print (new_df) ...: observation1 observation2 date Time 2012-11-02 9:15:00 79.373668 224 9:16:00 ... WebDec 9, 2016 · A series is like a dictionary, so you can use the .iteritems method: for idx, x in df ['a'].iteritems (): if x==4: print ('Index of that row: {}'.format (idx)) Great answer. But this answer more suites to be for a question which is how to loop through a dataframe column in the fastest possible way. This will work better as the model gets bigger ...
Find a Text in a List in Python - thisPointer
WebApr 8, 2024 · 1 Answer. You should use a user defined function that will replace the get_close_matches to each of your row. edit: lets try to create a separate column containing the matched 'COMPANY.' string, and then use the user defined function to replace it with the closest match based on the list of database.tablenames. WebYou can iterate over the index values if your dataframe has already been created. df = df.groupby ('l_customer_id_i').agg (lambda x: ','.join (x)) for name in df.index: print name print df.loc [name] Highly active question. Earn 10 reputation (not counting the association bonus) in order to answer this question. despicable me gru shrink the moon
Iterate over a dataframe to print the index and column and value
WebThis text can be a substring in any of the string element of the list. For this, we will use the enumerate () method to iterate over all the strings in the list, along with their index position. During iteration we will search for the text in the string, and if the string contains the text then we will mark its index position and break the loop. WebNov 3, 2024 · Here is an example of of some 5-minute data I am importing, indexing, and using to_datetime. It takes a while and it would be nice to see a progress bar. #Import csv files into a Pandas dataframes and convert to Pandas datetime and set to index eurusd_ask = pd.read_csv ('EURUSD_Candlestick_5_m_ASK_01.01.2012-05.08.2024.csv') … WebMar 22, 2024 · 2. pandas dataframe and series have iteration methods. So to iterate over index and a given column you can use iteritems: df ['new_col'] = [x if y == '1' and z =='2' for x, y in df ['col_2'].iteritems ()] In this case x is the index and y the value of column col2. More generally iterrows gives you access to index and all columns in one iteration: chuck taylor lift ox